Chemistry important questions are one of the most concerned topics for the students for the betterment of knowledge gathering prior to appearing on the exam of the respective subject. In order to be ready for appearing in any kind of exam, the learners needed better concentration and learning assessment of the particular subject. Solving questions about a particular subject helps the learners to get in-depth knowledge.
In order to support the requirement of the learners, the present tutorial will explain the advantages that the learners can get by solving questions regarding chemistry before appearing on an exam. In some cases, it has been seen that the student may remain in doubt about some specific parts of the concerning chapters of chemistry. The question-solving sessions can be helpful in such cases as the deep assessment helps to understand the subject in a better way.
Q1. Why does the electrical conductivity of semiconductors increase with a rise in temperature?
Ans. In semiconductors, the energy gaps lie between conduction bands and valence bond are small. The temperature increases, the more the kinetic energy of electrons increases, which helps the electrical conductivity as well.
Q2. What is the significance of the constant KH of the Henry’s Law?
Ans. The comparison of relative solubility of different gases is conducted by using Henry’s Law’s constant KH. It has been observed that the more the solubility of gas, the lesser is the value of the constant.
Figure 1: Henry’s Law
Q3. What is electrode potential?
Ans. The appearance of the electrode potential is observed at the interface between the electrolyte and the electrode at the time of transferring charged spices across the interface.
Q4. Why the fuels do not burn by themselves at room temperature while the availability of oxygen is plenty in the air?
Ans. The required energy for the activation of the reaction named combustion is very high which cannot be found at room temperature. Therefore, the fuels do not remain in such a position of being combusted by themselves under room temperature.
Q5. What happens when an electric field is applied to a colloidal solution?
Figure 2: Colloidal solution
Ans. The particles of the colloidal solution move towards the electron when the electric field is applied to such kinds of solutions. The particles that are positively charged move towards the cathode and the negatively charged particles move toward the anode.
Q6. What is the way of copper extraction from low-grade copper ores?
Ans. The method is used for the extraction of the coppers from the low-grade copper ores is termed as the hydrometallurgy method. The solution contains Cu2+ is treated with H2 and scrap iron.
Q7. Why the nitric oxide is paramagnetic in a gaseous state?
Ans. In a gaseous state, $\mathrm{NO_2}$ exists as a monomer with one unpaired electron. Therefore, the nitric oxide remains paramagnetic in a gaseous state.
Q8. Why does copper not replace the hydrogen atom from acids?
Ans. The main reason for not replacing any Hydrogen atom from acids is that copper has an electron value that is positive. With an electrode potential of 0.0 V, the positive value of the electron restrict the element to react with hydrogen.
Q9. Why does $\mathrm{[Fe(HO)_6]^{3+}}$ has a magnetic moment value of 5.92 BM, whereas the value of $\mathrm{[Fe(CN)_6]^{3-}}$ is 1.74 BM?
Ans. $\mathrm{d^2sp^3}$ hybridisation is involved in $\mathrm{[Fe(HO)_6]^{3+}}$ with an unpaired electron, whereas sp3d2 has been involved with five unpaired electrons in $\mathrm{[Fe(H_2O)_6]^{3+}}$. Due to this particular difference, these two elements have different magnetic moment values.
Q10. In which way the preparation of Monobromobenzene can be conducted from aniline?
Ans. The reaction using which the preparation of Monobromobenzene can be made is termed Sandmeyer's reaction. In a time of suspension of aniline in cold mineral acid, diazonium salt is formed. Formation of Monobromobenzene is done by the mixing these elements with cuprous bromide.
Q11. Write a reagent at the time of conversion to ethanoic acid from ethanol?
Ans. Acidified $\mathrm{K_2Cr_2O_7}$ or the element named $\mathrm{KMnO_4}$ is used in order to convert to ethanoic acid from the ethanol. Both the elements are considered powerful oxidisers.
Q12. Why do the Carboxylic acids not show the nucleophilic addition reaction?
Ans. The main reason is the resonance for which the carboxylic acid groups do not have the ability to show nucleophilic addition reaction.
This tutorial has included different questions that are acknowledged as the important ones for the learners. The learners needs to put some analysing technique while preparing for the examination, this tutorial has explained the advantages of solving chemistry questions prior to being seated on the exam as it helps the students to get in-depth knowledge about any particular chapter.
Q1. What was the purpose of asking questions while learning?
Ans. In the time of learning, the questioning technique is considered to be the most important one for better acquisition of the subject with the learner. The learners get an opportunity of driving clear ideas that appeal to the development of clear knowledge.
Q2. Why problem-solving questions are considered important in chemistry?
Ans. The subject of chemistry is often known as one of the complex subjects that can raise numerous doubts among learners. Rising problem-solving questions while teaching chemistry often help the learners to clear those raised doubts at the time of learning that contributes to the enhancement of engagement with the subject.
Q3. How do the solving questions techniques appeal to the problem-solving skills of learners?
Ans. Learning chemistry often requires a learner’s problem-solving skills in order to find the solution to different chemical reactions. Solving questions based on each chapter of chemistry allows the learners to revisit the past problems and ask open-ended questions that become an aid for doubt-clearance.
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